#list删除多个连续元素

list删除多个连续元素

或者 list删除超过数量的元素

list.subList(1,3).clear()

• subList(1, 3)： 取从 第1(包含) 到 第3(不包含) 的这几个元素的子集
• clear()： 将这个子集清空

   LinkedList<Integer> list = new LinkedList<>();
        list.addLast(1);
        list.addLast(2);
        list.addLast(3);
        list.addLast(4);
        list.addLast(5);
        list.addLast(6);
       //截取的这个list.跟原list息息相关!
        List<Integer> list1 = list.subList(2, 4);
        System.out.println(list1.toString());

        list1.clear();
        System.out.println(list.toString());


[3, 4]
[1, 2, 5, 6]

Returns a view of the portion of this list between the specified fromIndex, inclusive, and toIndex, exclusive. (If fromIndex and toIndex are equal, the returned list is empty.) The returned list is backed by this list, so non-structural changes in the returned list are reflected in this list, and vice-versa. The returned list supports all of the optional list operations supported by this list.

This method eliminates the need for explicit range operations (of the sort that commonly exist for arrays). Any operation that expects a list can be used as a range operation by passing a subList view instead of a whole list. For example, the following idiom removes a range of elements from a list:

  list.subList(from, to).clear();

Similar idioms may be constructed for indexOf and lastIndexOf, and all of the algorithms in the Collections class can be applied to a subList.

The semantics of the list returned by this method become undefined if the backing list (i.e., this list) is structurally modified in any way other than via the returned list. (Structural modifications are those that change the size of this list, or otherwise perturb it in such a fashion that iterations in progress may yield incorrect results.)